Integrand size = 26, antiderivative size = 86 \[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^3 \, dx=\frac {i 2^{3+\frac {m}{2}} a^3 \operatorname {Hypergeometric2F1}\left (-2-\frac {m}{2},\frac {m}{2},\frac {2+m}{2},\frac {1}{2} (1-i \tan (c+d x))\right ) (e \sec (c+d x))^m (1+i \tan (c+d x))^{-m/2}}{d m} \]
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Time = 0.18 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {3586, 3604, 72, 71} \[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^3 \, dx=\frac {i a^3 2^{\frac {m}{2}+3} (1+i \tan (c+d x))^{-m/2} (e \sec (c+d x))^m \operatorname {Hypergeometric2F1}\left (-\frac {m}{2}-2,\frac {m}{2},\frac {m+2}{2},\frac {1}{2} (1-i \tan (c+d x))\right )}{d m} \]
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Rule 71
Rule 72
Rule 3586
Rule 3604
Rubi steps \begin{align*} \text {integral}& = \left ((e \sec (c+d x))^m (a-i a \tan (c+d x))^{-m/2} (a+i a \tan (c+d x))^{-m/2}\right ) \int (a-i a \tan (c+d x))^{m/2} (a+i a \tan (c+d x))^{3+\frac {m}{2}} \, dx \\ & = \frac {\left (a^2 (e \sec (c+d x))^m (a-i a \tan (c+d x))^{-m/2} (a+i a \tan (c+d x))^{-m/2}\right ) \text {Subst}\left (\int (a-i a x)^{-1+\frac {m}{2}} (a+i a x)^{2+\frac {m}{2}} \, dx,x,\tan (c+d x)\right )}{d} \\ & = \frac {\left (2^{2+\frac {m}{2}} a^4 (e \sec (c+d x))^m (a-i a \tan (c+d x))^{-m/2} \left (\frac {a+i a \tan (c+d x)}{a}\right )^{-m/2}\right ) \text {Subst}\left (\int \left (\frac {1}{2}+\frac {i x}{2}\right )^{2+\frac {m}{2}} (a-i a x)^{-1+\frac {m}{2}} \, dx,x,\tan (c+d x)\right )}{d} \\ & = \frac {i 2^{3+\frac {m}{2}} a^3 \operatorname {Hypergeometric2F1}\left (-2-\frac {m}{2},\frac {m}{2},\frac {2+m}{2},\frac {1}{2} (1-i \tan (c+d x))\right ) (e \sec (c+d x))^m (1+i \tan (c+d x))^{-m/2}}{d m} \\ \end{align*}
Time = 1.55 (sec) , antiderivative size = 147, normalized size of antiderivative = 1.71 \[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^3 \, dx=-\frac {i a^3 (e \sec (c+d x))^m \left (-3 i (2+m) \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},\frac {m}{2},\frac {2+m}{2},\sec ^2(c+d x)\right ) \tan (c+d x)-i (2+m) \operatorname {Hypergeometric2F1}\left (\frac {1}{2},\frac {m}{2},\frac {2+m}{2},\sec ^2(c+d x)\right ) \tan (c+d x)+\left (-8-4 m+m \sec ^2(c+d x)\right ) \sqrt {-\tan ^2(c+d x)}\right )}{d m (2+m) \sqrt {-\tan ^2(c+d x)}} \]
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\[\int \left (e \sec \left (d x +c \right )\right )^{m} \left (a +i a \tan \left (d x +c \right )\right )^{3}d x\]
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\[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^3 \, dx=\int { {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{3} \left (e \sec \left (d x + c\right )\right )^{m} \,d x } \]
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\[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^3 \, dx=- i a^{3} \left (\int i \left (e \sec {\left (c + d x \right )}\right )^{m}\, dx + \int \left (- 3 \left (e \sec {\left (c + d x \right )}\right )^{m} \tan {\left (c + d x \right )}\right )\, dx + \int \left (e \sec {\left (c + d x \right )}\right )^{m} \tan ^{3}{\left (c + d x \right )}\, dx + \int \left (- 3 i \left (e \sec {\left (c + d x \right )}\right )^{m} \tan ^{2}{\left (c + d x \right )}\right )\, dx\right ) \]
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\[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^3 \, dx=\int { {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{3} \left (e \sec \left (d x + c\right )\right )^{m} \,d x } \]
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\[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^3 \, dx=\int { {\left (i \, a \tan \left (d x + c\right ) + a\right )}^{3} \left (e \sec \left (d x + c\right )\right )^{m} \,d x } \]
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Timed out. \[ \int (e \sec (c+d x))^m (a+i a \tan (c+d x))^3 \, dx=\int {\left (\frac {e}{\cos \left (c+d\,x\right )}\right )}^m\,{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^3 \,d x \]
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